题解byliuhaonan
#include <iostream>
using namespace std;
int a[105][105],f[105][105],r,c; //f数组记忆化
const int dx[4] = {-1,1,0,0}; //增量数组
const int dy[4] = {0,0,-1,1};
int DFS(int x,int y) //目前在点(x,y)
{
if(f[x][y] != 0) return f[x][y]; //如果曾经走到过这个点
f[x][y] = 1;
for(int i = 0;i < 4;i++) //四个方向
{
int next_x,next_y;
next_x = x + dx[i];
next_y = y + dy[i];
if(next_x >= 1&&next_x <= r&&next_y >= 1&&next_y <= c&&a[next_x][next_y] < a[x][y]) f[x][y] = max(f[x][y],DFS(next_x,next_y) + 1); //如果下个点合法,记录最大值
}
return f[x][y];
}
int main()
{
int i,j,maxn = -1000000000;
cin>>r>>c;
for(i = 1;i <= r;i++) for(j = 1;j <= c;j++) cin>>a[i][j];
for(i = 1;i <= r;i++) for(j = 1;j <= c;j++) maxn = max(maxn,DFS(i,j)); //枚举起点
cout<<maxn<<endl;
return 0; //华丽结尾
}