提交时间:2024-08-19 15:26:02

运行 ID: 166850

#include <bits/stdc++.h> using namespace std; int main() { int T; cin>>T; int n[T]; for (int i = 0;i<T;i++) { cin>>n[i]; } for (int i = 0;i<T;i++) { if ((n[i]&(n[i]-1)) == 0) { cout<<"Yes"<<endl; } else { cout<<"No"<<endl; } } return 0; }