提交时间:2024-08-20 18:26:08

运行 ID: 169859

#include <iostream> using namespace std; void mi(int n) { int b[32]; int len = 0; while (n > 0) { b[len++] = n % 2; n = n / 2; } for (int i = len - 1; i >= 0; i--) { if (b[i] == 1) { if (i != len - 1) { cout << "+"; } if (i == 0) { cout << "2(0)"; } else if (i == 1) { cout << "2"; } else { cout << "2("; mi(i); cout << ")"; } } } } int main() { int n; cin >> n; mi(n); return 0; }