using namespace std;
string multiple(string a, string b) //计算两高精度数乘积 {
int i, j;
string result = "0";
for(i = a.length() - 1; i >= 0; i--)
{
int remain = 0;
string str = "";
for(j = b.length() - 1; j >= 0; j--)
{
int tmp = (a[i] - '0') * (b[j] - '0') + remain;
remain = tmp / 10;
str = (char)(tmp % 10 + '0') + str;
}
if(remain != 0)
{
str = (char)(remain + '0') + str;
}
int tmp = 0;
int m = result.length() - (a.length() - i);
int n = str.length() - 1;
remain = 0;
while(m >= 0 && n >= 0)
{
tmp = (result[m] - '0') + (str[n] - '0') + remain;
remain = tmp / 10;
result[m] = (char)(tmp % 10 + '0');
m--;
n--;
}
while(m >= 0)
{
tmp = (result[m] - '0') + remain;
remain = tmp / 10;
result[m] = (char)(tmp % 10 + '0');
m--;
}
while(n >= 0)
{
tmp = (str[n] - '0') + remain;
remain = tmp / 10;
result = (char)(tmp % 10 + '0') + result;
n--;
}
if(remain != 0)
{
result = (char)(remain + '0') + result;
}
}
return result;
}
int main() {
int n, i, j;
string str;
while(cin >> str >> n)
{
string res = "";
int pos = str.find_first_of(".");
if(pos != string::npos)
{
str.erase(pos, 1);
}
int num = str.length() - pos;
if(n == 1) //计算str表示的数的n次幂
{
res = str;
}
else
{
res = multiple(str, str);
for(i = 2; i < n; i++)
{
res = multiple(res, str);
}
}
if(pos == string::npos)
{
cout << res << endl;
continue;
}
int c = num * n;
i = res.length() - 1;
string s = "";
while(c > 0 && i >= 0)
{
s = res[i--] + s;
c--;
}
s = "." + s;
for(j = 0; j <= i; j++)
{
if(res[j] != '0')
{
s = res.substr(j, i - j + 1) + s;
break;
}
}
for(i = s.length() - 1; i >= 0; i--)
{
if(s[i] == '0') //消除前导0
{
s.erase(i, 1);
}
else
{
break;
}
}
if(s[s.length() - 1] == '.')
{
s.erase(s.length() - 1, 1);
}
cout << s << endl;
}
return 0;
}
比赛已结束。